121 lines
3.8 KiB
SQL
121 lines
3.8 KiB
SQL
-- 福利品用户筛选：第一步 - 查询符合条件的用户和订单
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-- 修正版：去重 + 排除异常低价订单（pay_amount_int < 100000，即<1000元）
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WITH
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target_orders AS (
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SELECT
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o.account_id,
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o.trade_no,
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o.goods_id,
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o.goods_name,
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o.key_from,
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o.pay_success_date,
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o.pay_amount_int,
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o.order_status
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FROM bi_vala_order o
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JOIN bi_vala_app_account a ON o.account_id = a.id AND a.status = 1
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WHERE o.goods_id IN (31, 60, 61)
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AND o.order_status IN (3, 4)
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AND o.pay_success_date IS NOT NULL
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AND o.pay_amount_int >= 100000 -- 排除异常低价订单
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),
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refund_info AS (
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SELECT trade_no, refund_amount_int
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FROM bi_refund_order
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WHERE status = 3
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),
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order_with_refund AS (
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SELECT
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t.*,
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r.refund_amount_int AS refund_amt,
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CASE
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WHEN r.refund_amount_int IS NULL THEN 'none'
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WHEN r.refund_amount_int < t.pay_amount_int THEN 'partial'
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ELSE 'full'
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END AS refund_type
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FROM target_orders t
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LEFT JOIN refund_info r ON t.trade_no = r.trade_no
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),
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-- 情况1: goods_id=61, 无任何退费
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case1_users AS (
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SELECT DISTINCT account_id FROM order_with_refund
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WHERE goods_id = 61 AND refund_type = 'none'
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),
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-- 情况2: goods_id IN (31,60), >=2笔有效订单, 最多一笔400元部分退费
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case2_eligible AS (
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SELECT account_id
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FROM order_with_refund
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WHERE goods_id IN (31, 60) AND refund_type != 'full'
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GROUP BY account_id
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HAVING COUNT(*) >= 2
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AND SUM(CASE WHEN refund_type = 'partial' AND refund_amt = 40000 THEN 1 ELSE 0 END) <= 1
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AND SUM(CASE WHEN refund_type = 'partial' AND refund_amt != 40000 THEN 1 ELSE 0 END) = 0
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),
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case2_users AS (
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SELECT DISTINCT account_id FROM case2_eligible
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),
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-- 情况3: goods_id IN (31,60) 无退费 + goods_id=61 退费1999
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case3_has_31_60 AS (
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SELECT DISTINCT account_id FROM order_with_refund
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WHERE goods_id IN (31, 60) AND refund_type = 'none'
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),
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case3_has_61_1999 AS (
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SELECT DISTINCT account_id FROM order_with_refund
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WHERE goods_id = 61 AND refund_type = 'partial' AND refund_amt = 199900
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),
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case3_users AS (
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SELECT a.account_id
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FROM case3_has_31_60 a
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JOIN case3_has_61_1999 b ON a.account_id = b.account_id
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),
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-- 合并所有符合条件的用户，记录每个用户属于哪些情况
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all_eligible_users AS (
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SELECT account_id, '情况1' AS case_type FROM case1_users
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UNION
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SELECT account_id, '情况2' AS case_type FROM case2_users
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UNION
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SELECT account_id, '情况3' AS case_type FROM case3_users
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),
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-- 按用户汇总归属情况
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user_cases AS (
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SELECT
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account_id,
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STRING_AGG(DISTINCT case_type, '+' ORDER BY case_type) AS case_labels
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FROM all_eligible_users
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GROUP BY account_id
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),
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-- 所有符合条件的订单（去重）
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eligible_orders AS (
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-- 情况1的订单
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SELECT * FROM order_with_refund WHERE goods_id = 61 AND refund_type = 'none' AND account_id IN (SELECT account_id FROM case1_users)
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UNION
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-- 情况2的订单
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SELECT * FROM order_with_refund WHERE goods_id IN (31, 60) AND refund_type != 'full' AND account_id IN (SELECT account_id FROM case2_users)
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UNION
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-- 情况3的订单
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SELECT * FROM order_with_refund
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WHERE (goods_id IN (31, 60) AND refund_type = 'none' AND account_id IN (SELECT account_id FROM case3_users))
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OR (goods_id = 61 AND refund_type = 'partial' AND refund_amt = 199900 AND account_id IN (SELECT account_id FROM case3_users))
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)
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SELECT
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eo.account_id AS "用户ID",
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eo.trade_no AS "交易号",
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eo.goods_id AS "商品ID",
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eo.goods_name AS "商品名称",
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eo.key_from AS "渠道",
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TO_CHAR(eo.pay_success_date, 'YYYY-MM-DD HH24:MI:SS') AS "购课日期",
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eo.pay_amount_int / 100.0 AS "支付金额(元)",
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eo.refund_amt / 100.0 AS "退款金额(元)",
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eo.refund_type AS "退费状态",
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uc.case_labels AS "来源情况"
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FROM eligible_orders eo
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JOIN user_cases uc ON eo.account_id = uc.account_id
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ORDER BY eo.account_id, eo.goods_id, eo.trade_no;
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