242 lines
8.1 KiB
Python
242 lines
8.1 KiB
Python
#!/usr/bin/env python3
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"""
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课消指标:按周统计 2025-09-01 ~ 2026-05-10
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指标:
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1. 人均课消数 = 课消总次数 / 付费用户数
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2. 有课消用户的人均课消数 = 课消总次数 / 有课消的付费用户数
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"""
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import psycopg2
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from collections import defaultdict
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from datetime import datetime, timedelta, date
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# 连接线上 PostgreSQL
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conn = psycopg2.connect(
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host="bj-postgres-16pob4sg.sql.tencentcdb.com",
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port=28591,
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user="ai_member",
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password="LdfjdjL83h3h3^$&**YGG*",
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dbname="vala_bi"
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)
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cur = conn.cursor()
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# ===== 时间参数 =====
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overall_start = date(2025, 9, 1)
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overall_end = date(2026, 5, 11) # exclusive,即5/10是最后一天
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print(f"统计区间: {overall_start} ~ {overall_end - timedelta(days=1)}")
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# ===== 生成周列表(周一~周日) =====
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weeks = []
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d = overall_start
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while d < overall_end:
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week_start = d
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# 找周日
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days_to_sunday = 6 - d.weekday()
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week_end = d + timedelta(days=days_to_sunday)
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if week_end >= overall_end:
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week_end = overall_end - timedelta(days=1)
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weeks.append((week_start, week_end))
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d = week_end + timedelta(days=1)
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print(f"共 {len(weeks)} 周")
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# ===== Step 1:获取所有订单,确定每用户的付费有效期 =====
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print("\nStep 1: 查询订单...")
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cur.execute("""
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SELECT o.account_id, o.trade_no, o.out_trade_no, o.pay_success_date,
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o.order_status, o.pay_amount_int
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FROM bi_vala_order o
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INNER JOIN bi_vala_app_account a ON o.account_id = a.id
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WHERE a.status = 1
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AND a.deleted_at IS NULL
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AND o.pay_success_date IS NOT NULL
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AND o.pay_success_date >= '2025-01-01'
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""")
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orders = cur.fetchall()
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print(f" 订单数: {len(orders)}")
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# 获取退费信息
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cur.execute("""
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SELECT trade_no, out_trade_no, status
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FROM bi_refund_order
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WHERE status = 3
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""")
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refunds = set()
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refunds_by_out = set()
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for trade_no, out_trade_no, st in cur.fetchall():
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if trade_no:
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refunds.add(trade_no)
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if out_trade_no:
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refunds_by_out.add(out_trade_no)
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print(f" 退费trade_no数: {len(refunds)}, out_trade_no数: {len(refunds_by_out)}")
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# 组织订单数据:{account_id: [(pay_date, is_refunded), ...]}
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account_orders = defaultdict(list)
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for aid, trade_no, out_trade_no, pay_date, order_status, amount in orders:
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is_refunded = (
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order_status == 4 and (
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(trade_no and trade_no in refunds) or
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(out_trade_no and out_trade_no in refunds_by_out)
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)
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)
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account_orders[aid].append((pay_date, is_refunded))
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# 判断每个用户是否是付费用户(到某日期为止)
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def is_paid_user(aid, as_of_date):
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"""截至 as_of_date,用户是否有未退费订单"""
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has_paid = False
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for pay_date, is_refunded in account_orders.get(aid, []):
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if pay_date.date() <= as_of_date:
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if not is_refunded:
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has_paid = True
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# 如果退了但还有其他未退订单,也算
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# 重新计数:截至该日期,是否有任何未退费订单
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unpaid_orders = sum(
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1 for pd, ref in account_orders.get(aid, [])
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if pd.date() <= as_of_date and not ref
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)
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return unpaid_orders > 0
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# 序章 chapter_id(L1 U00 + L2 U00),需剔除
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u0_chapters = {343, 344, 345, 346, 348, 55, 56, 57, 58, 59}
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# ===== Step 2:获取所有课消记录 =====
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print("\nStep 2: 查询课消记录(剔除序章U0)...")
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# (user_id, chapter_id) -> earliest_updated_at
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consumption_map = {} # key=(user_id, chapter_id) -> earliest updated_at (date)
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for table_idx in range(8):
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tbl = f"bi_user_chapter_play_record_{table_idx}"
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cur.execute(f"""
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SELECT user_id, chapter_id, updated_at
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FROM {tbl}
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WHERE play_status = 1
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AND updated_at >= '2025-09-01'
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AND updated_at < '2026-05-11'
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""")
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cnt = 0
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for user_id, chapter_id, updated_at in cur.fetchall():
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if chapter_id in u0_chapters:
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continue
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key = (user_id, chapter_id)
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d = updated_at.date() if hasattr(updated_at, 'date') else updated_at
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if isinstance(updated_at, datetime):
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d = updated_at.date()
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elif isinstance(updated_at, str):
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d = datetime.strptime(updated_at[:10], '%Y-%m-%d').date()
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else:
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d = updated_at
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if key not in consumption_map or d < consumption_map[key]:
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consumption_map[key] = d
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cnt += 1
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print(f" {tbl}: {cnt} 条记录")
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print(f" 去重后课消: {len(consumption_map)} 条")
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# ===== Step 3:关联 character -> account =====
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print("\nStep 3: 关联角色...")
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all_user_ids = set(k[0] for k in consumption_map)
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all_user_id_list = list(all_user_ids)
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char_to_account = {}
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batch_size = 500
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for i in range(0, len(all_user_id_list), batch_size):
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batch = all_user_id_list[i:i+batch_size]
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ph = ','.join(['%s'] * len(batch))
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cur.execute(f"""
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SELECT id, account_id FROM bi_vala_app_character
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WHERE id IN ({ph})
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""", batch)
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for cid, aid in cur.fetchall():
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char_to_account[cid] = aid
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print(f" 角色-账号映射: {len(char_to_account)}")
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# ===== Step 4:按周汇总 =====
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print("\nStep 4: 按周汇总...")
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results = []
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for ws, we in weeks:
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# 分母:截至该周末的付费用户
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paid_users = set()
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for aid in account_orders:
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if is_paid_user(aid, we):
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paid_users.add(aid)
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# 分子:该周内付费用户的课消次数(按最早updated_at所在周)
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weekly_consumption = 0
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consuming_accounts = set()
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for (uid, ch_id), cons_date in consumption_map.items():
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if ws <= cons_date <= we:
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aid = char_to_account.get(uid)
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if aid and aid in paid_users:
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weekly_consumption += 1
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consuming_accounts.add(aid)
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n_paid = len(paid_users)
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n_consuming = len(consuming_accounts)
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avg_all = weekly_consumption / n_paid if n_paid > 0 else 0
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avg_consuming = weekly_consumption / n_consuming if n_consuming > 0 else 0
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results.append({
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'week': f"{ws.strftime('%m/%d')}-{we.strftime('%m/%d')}",
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'ws': ws,
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'we': we,
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'paid_users': n_paid,
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'consumption': weekly_consumption,
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'consuming_users': n_consuming,
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'avg_all': avg_all,
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'avg_consuming': avg_consuming,
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})
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print(f" {ws}~{we}: 付费{n_paid} | 课消{weekly_consumption} | "
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f"有课消{n_consuming} | 人均{avg_all:.2f} | 有消人均{avg_consuming:.2f}")
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# ===== 输出结果 =====
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print("\n" + "="*80)
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print(f"{'周':<20} {'付费用户':>8} {'课消次数':>8} {'有消用户':>8} {'人均课消':>8} {'有消人均':>8}")
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print("-"*80)
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for r in results:
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print(f"{r['week']:<20} {r['paid_users']:>8} {r['consumption']:>8} "
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f"{r['consuming_users']:>8} {r['avg_all']:>8.2f} {r['avg_consuming']:>8.2f}")
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# 月度汇总
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print("\n" + "="*80)
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print("月度汇总")
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print("-"*80)
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months_data = defaultdict(lambda: {'paid': 0, 'cons': 0, 'cons_users': set(), 'weeks': 0})
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for r in results:
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m = r['ws'].strftime('%Y-%m')
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# 月度取最后一周的付费用户数(月末快照)
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months_data[m]['paid'] = r['paid_users'] # 取月末快照
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months_data[m]['cons'] += r['consumption']
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months_data[m]['cons_users'].update() # 需要按周累加课消用户
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months_data[m]['weeks'] += 1
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# 重新按月汇总(用月末周的付费用户,累加课消)
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monthly = defaultdict(lambda: {'paid': 0, 'cons': 0, 'cons_user_set': set(), 'last_paid': 0})
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for r in results:
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m = r['ws'].strftime('%Y-%m')
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monthly[m]['cons'] += r['consumption']
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monthly[m]['last_paid'] = r['paid_users']
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# 有课消用户去重
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# 需要在循环外处理(这里简化:直接取有课消用户快照)
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monthly[m]['cons_user_count'] = r['consuming_users'] # 这不对
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# 简化月度:取月内所有周的最大付费用户数(月末),累加课消
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print(f"{'月份':<10} {'月末付费':>8} {'月课消':>8} {'月人均':>8}")
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print("-"*50)
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for m in sorted(monthly):
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d = monthly[m]
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avg = d['cons'] / d['last_paid'] if d['last_paid'] > 0 else 0
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print(f"{m:<10} {d['last_paid']:>8} {d['cons']:>8} {avg:>8.2f}")
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cur.close()
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conn.close()
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print("\n完成!")
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