139 lines
4.7 KiB
SQL
139 lines
4.7 KiB
SQL
-- 福利品用户筛选：拥有两个年包课包（level1或level2各算一个年包）
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-- goods_id: 31=level2/年包, 60=level1, 61=level1+2(算两个年包)
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WITH
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-- 目标订单（仅已完成/已退款，剔除测试账号）
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target_orders AS (
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SELECT
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o.account_id,
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o.trade_no,
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o.goods_id,
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o.goods_name,
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o.key_from,
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o.pay_success_date,
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o.pay_amount_int,
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o.order_status
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FROM vala_bi.bi_vala_order o
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JOIN vala_bi.bi_vala_app_account a ON o.account_id = a.id AND a.status = 1
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WHERE o.goods_id IN (31, 60, 61)
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AND o.order_status IN (3, 4)
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AND o.pay_success_date IS NOT NULL
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),
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-- 退费信息（仅退费成功）
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refund_info AS (
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SELECT
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trade_no,
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refund_amount_int
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FROM vala_bi.bi_refund_order
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WHERE status = 3
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),
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-- 订单 + 退费标记
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order_with_refund AS (
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SELECT
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t.*,
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r.refund_amount_int AS refund_amt,
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CASE
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WHEN r.refund_amount_int IS NULL THEN 'none'
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WHEN r.refund_amount_int < t.pay_amount_int THEN 'partial'
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ELSE 'full'
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END AS refund_type
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FROM target_orders t
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LEFT JOIN refund_info r ON t.trade_no = r.trade_no
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),
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-- ===== 情况1: goods_id=61, 无任何退费 =====
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case1_users AS (
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SELECT DISTINCT account_id
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FROM order_with_refund
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WHERE goods_id = 61 AND refund_type = 'none'
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),
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-- ===== 情况2: goods_id IN (31,60), >=2笔有效订单, 最多一笔400元部分退费 =====
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case2_eligible AS (
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SELECT
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account_id,
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COUNT(*) AS total_valid,
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SUM(CASE WHEN refund_type = 'none' THEN 1 ELSE 0 END) AS no_refund_cnt,
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SUM(CASE WHEN refund_type = 'partial' AND refund_amt = 40000 THEN 1 ELSE 0 END) AS partial_400_cnt,
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SUM(CASE WHEN refund_type = 'full' THEN 1 ELSE 0 END) AS full_refund_cnt,
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SUM(CASE WHEN refund_type = 'partial' AND refund_amt != 40000 THEN 1 ELSE 0 END) AS other_partial_cnt
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FROM order_with_refund
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WHERE goods_id IN (31, 60)
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AND refund_type != 'full' -- 排除全额退款
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GROUP BY account_id
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HAVING COUNT(*) >= 2
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AND SUM(CASE WHEN refund_type = 'partial' AND refund_amt = 40000 THEN 1 ELSE 0 END) <= 1
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AND SUM(CASE WHEN refund_type = 'partial' AND refund_amt != 40000 THEN 1 ELSE 0 END) = 0
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),
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-- 排除全额退款的无效订单后的明细
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case2_valid_orders AS (
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SELECT *
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FROM order_with_refund
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WHERE goods_id IN (31, 60) AND refund_type != 'full'
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),
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case2_users AS (
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SELECT DISTINCT account_id FROM case2_eligible
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),
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-- ===== 情况3: goods_id IN (31,60) 至少一笔无退费 + goods_id=61 一笔退费1999 =====
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case3_has_31_60 AS (
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SELECT DISTINCT account_id
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FROM order_with_refund
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WHERE goods_id IN (31, 60) AND refund_type = 'none'
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),
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case3_has_61_1999 AS (
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SELECT DISTINCT account_id
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FROM order_with_refund
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WHERE goods_id = 61 AND refund_type = 'partial' AND refund_amt = 199900
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),
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case3_users AS (
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SELECT a.account_id
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FROM case3_has_31_60 a
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JOIN case3_has_61_1999 b ON a.account_id = b.account_id
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),
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-- ===== 合并所有符合条件的用户 =====
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all_eligible_users AS (
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SELECT account_id FROM case1_users
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UNION
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SELECT account_id FROM case2_users
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UNION
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SELECT account_id FROM case3_users
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)
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-- ===== 最终输出：符合条件的用户 + 其所有相关订单 + parent_address =====
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SELECT
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ou.account_id::text AS "用户ID",
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r.trade_no AS "交易号",
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r.goods_id AS "商品ID",
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r.goods_name AS "商品名称",
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r.key_from AS "渠道",
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r.pay_success_date AS "购课日期",
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r.pay_amount_int / 100.0 AS "支付金额(元)",
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r.refund_amt / 100.0 AS "退款金额(元)",
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r.refund_type AS "退费状态",
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pa.name AS "收件人",
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pa.phone_number AS "电话",
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pa.region AS "区域",
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pa.address AS "地址",
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CASE
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WHEN ou.account_id IN (SELECT account_id FROM case1_users) THEN '情况1'
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WHEN ou.account_id IN (SELECT account_id FROM case2_users) THEN '情况2'
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WHEN ou.account_id IN (SELECT account_id FROM case3_users) THEN '情况3'
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END AS "来源情况"
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FROM all_eligible_users ou
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JOIN (
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-- 输出情况1的订单
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SELECT * FROM order_with_refund WHERE goods_id = 61 AND refund_type = 'none' AND account_id IN (SELECT account_id FROM case1_users)
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UNION ALL
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-- 输出情况2的订单（仅有效订单）
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SELECT * FROM case2_valid_orders WHERE account_id IN (SELECT account_id FROM case2_users)
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UNION ALL
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-- 输出情况3的订单（包含31/60无退费 + 61退费1999）
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SELECT * FROM order_with_refund
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WHERE (goods_id IN (31, 60) AND refund_type = 'none' AND account_id IN (SELECT account_id FROM case3_users))
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OR (goods_id = 61 AND refund_type = 'partial' AND refund_amt = 199900 AND account_id IN (SELECT account_id FROM case3_users))
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) r ON ou.account_id = r.account_id
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LEFT JOIN vala_class.parent_address pa ON ou.account_id::text = pa.account_id
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ORDER BY ou.account_id, r.goods_id, r.trade_no;
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